Exercise 3.6
Question 1:
Solve the following pairs of equations by reducing them to a pair of linear equations:
Let
Using cross-multiplication method, we obtain
Putting
Multiplying equation (1) by 3, we obtain
6p + 9q = 6 (3)
Adding equation (2) and (3), we obtain
Putting in equation (1), we obtain
Hence,
Substituting
By cross-multiplication, we obtain
Putting
Multiplying equation (1) by 3, we obtain
Adding (2) an (3), we obtain
Putting this value in equation (1), we obtain
Putting
By cross-multiplication method, we obtain
Putting
By cross-multiplication method, we obtain
Hence, x = 1, y = 2
Putting
Using cross-multiplication method, we obtain
Adding equation (3) and (4), we obtain
Substituting in equation (3), we obtain
y = 2
Hence, x = 3, y = 2
Putting
Adding (1) and (2), we obtain
Substituting in (2), we obtain
Adding equations (3) and (4), we obtain
Substituting in (3), we obtain
Hence, x = 1, y = 1
Question 2:
Formulate the following problems as a pair of equations, and hence find their solutions:
(i) Ritu can row downstream 20 km in 2 hours, and upstream 4 km in 2 hours. Find her speed of rowing in still water and the speed of the current.
(ii) 2 women and 5 men can together finish an embroidery work in 4 days, while 3 women and 6 men can finish it in 3 days. Find the time taken by 1 woman alone to finish the work, and also that taken by 1 man alone.
(iii) Roohi travels 300 km to her home partly by train and partly by bus. She takes 4 hours if she travels 60 km by train and remaining by bus. If she travels 100 km by train and the remaining by bus, she takes 10 minutes longer. Find the speed of the train and the bus separately.
(i)Let the speed of Ritu in still water and the speed of stream be x km/h
and y km/h respectively.
Speed of Ritu while rowing
Upstream =
km/h
Downstream =
km/h
According to question,

Adding equation (1) and (2), we obtain

Putting this in equation (1), we obtain
y = 4
Hence, Ritu’s speed in still water is 6 km/h and the speed of the current is 4 km/h.
(ii)Let the number of days taken by a woman and a man be x and y respectively.
Therefore, work done by a woman in 1 day =
Work done by a man in 1 day =
According to the question,

Putting
in these equations, we obtain

By cross-multiplication, we obtain


Hence, number of days taken by a woman = 18
Number of days taken by a man = 36
(iii) Let the speed of train and bus be u km/h and v km/h respectively.
According to the given information,

Putting
and
in these equations, we obtain

Multiplying equation (3) by 10, we obtain

Subtracting equation (4) from (5), we obtain

Substituting in equation (3), we obtain

Hence, speed of train = 60 km/h
Speed of bus = 80 km/h
and y km/h respectively.
Speed of Ritu while rowing
Upstream =
Downstream =
According to question,
Adding equation (1) and (2), we obtain
Putting this in equation (1), we obtain
y = 4
Hence, Ritu’s speed in still water is 6 km/h and the speed of the current is 4 km/h.
(ii)Let the number of days taken by a woman and a man be x and y respectively.
Therefore, work done by a woman in 1 day =
Work done by a man in 1 day =
According to the question,
Putting
By cross-multiplication, we obtain
Hence, number of days taken by a woman = 18
Number of days taken by a man = 36
(iii) Let the speed of train and bus be u km/h and v km/h respectively.
According to the given information,
Putting
Multiplying equation (3) by 10, we obtain
Subtracting equation (4) from (5), we obtain
Substituting in equation (3), we obtain
Hence, speed of train = 60 km/h
Speed of bus = 80 km/h
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